San Antonio de la Cal
San Antonio de la Cal is a city in Mexico with a population of about 20,198.
MexicoTown🏆 #499 most populated in Mexico🕐 America/Mexico_CitySan Antonio de la Cal is a town and municipality in Oaxaca in southeastern Mexico and is the fifth most densely populated municipality in Oaxaca; only four Oaxacan municipalities are more densely populated than it: Oaxaca, San Jacinto Amilpas, Santa Lucía del Camino, and Santa Cruz Amilpas. The municipality covers an area of 11 km2. It is part of the Centro District in the Valles Centrales region. As of 2005, the municipality had a total population of 15,071.
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About San Antonio de la Cal
| Country | Mexico |
| Continent | North America |
| Explore | 20 |
| Population | 20,198 |
| Local currency | MXN |
| Coordinates | 17.0292, -96.7009 |
| Time zone | America/Mexico_City |
🧭 Facts & curiosities
| Settlement type | Town |
| Distance to the capital | 370 km · Mexico City |
| Population (Mexico) | #499 most populated in Mexico |
| Where on Earth | 17°1′45″N · 96°42′3″W |
| Hemisphere | N · W |
| Distance to the equator | 1,896 km |
| Distance to the North Pole | 8,123 km |
| Did you know | More populous than 99% of all places |
| Same latitude as | Rajamahendravaram (India) |
| Antipode (other side of Earth) | -17.03, 83.30 |
✈️ Distance to major cities
| Los Angeles | 2,861 km |
| New York | 3,416 km |
| São Paulo | 7,065 km |
| London | 8,977 km |
| Paris | 9,231 km |
| Moscow | 10,863 km |