Sandy Hills
Sandy Hills is a city in United States with a population of about 89,575.
Sandy Hills was a small historic settlement which was located in western Wilson County, Texas United States, five miles west of La Vernia at the intersection of county roads 321 and 361. The settlement is now depopulated, with the sole remaining building being a small brick school house.
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About Sandy Hills
| Country | United States |
| Continent | North America |
| Explore | UT |
| Population | 89,575 |
| Local currency | USD |
| Coordinates | 40.5811, -111.8508 |
| Time zone | America/Denver |
| Elevation | 1,452 m |
🧭 Facts & curiosities
| Settlement type | Town |
| Distance to the capital | 2,963 km · Washington |
| Population (United States) | #420 most populated in United States |
| Where on Earth | 40°34′52″N · 111°51′3″W |
| Hemisphere | N · W |
| Distance to the equator | 4,517 km |
| Distance to the North Pole | 5,501 km |
| Did you know | More populous than 100% of all places |
| Same latitude as | Sumqayıt (Azerbaijan) |
| Antipode (other side of Earth) | -40.58, 68.15 |
✈️ Distance to major cities
| Los Angeles | 920 km |
| New York | 3,168 km |
| London | 7,837 km |
| Paris | 8,166 km |
| Tokyo | 8,831 km |
| Moscow | 8,922 km |